Reverse-side entry bound for Ruelle's Lemma 1.4 #
entry_reverse_bound_of_orthogonal: for an orthogonal matrix S (here S * Sᵀ = 1)
whose entries obey the graded forward bound |S a b| ≤ c · exp(-(max (g b - g a) 0)),
every entry obeys the reverse bound at the full pairwise rate:
|S i j| ≤ (d-1)! · c^(d-1) · exp(-(g i - g j)).
The argument is Ruelle's cofactor expansion: S⁻¹ = Sᵀ, entries of S⁻¹ are
(det S)-scaled cofactors with |det S| = 1, and each surviving Leibniz term of the
cofactor minor pays exactly the level imbalance g i - g j by telescoping.
The telescoping level identity: for a permutation σ of Fin d with σ j = i,
∑_{k ≠ j} (g k - g (σ k)) = g i - g j.
Per-permutation product bound. For a permutation σ of Fin d with σ j = i, the product of
the (d-1) entry-magnitudes off the j-column, bounded by the graded forward bound, is at most
c^(d-1) · exp(-(g i - g j)).
Reverse-side entry bound (Ruelle Lemma 1.4, reverse half).
Let S be an orthogonal matrix (S * Sᵀ = 1) whose entries obey the graded forward bound
|S a b| ≤ c · exp(-(max (g b - g a) 0)) (entries where the level g increases are exponentially
small). Then every entry obeys the reverse bound at the full pairwise rate:
|S i j| ≤ (d-1)! · c^(d-1) · exp(-(g i - g j)).
Proof: S⁻¹ = Sᵀ, so S i j is a (det S)-scaled cofactor with |det S| = 1; expanding the
cofactor minor by the Leibniz formula, every surviving permutation term pays exactly the level
imbalance g i - g j (telescoping), and there are at most (d-1)! of them.